Optimal. Leaf size=309 \[ -\frac{3 \sqrt{a+b x+c x^2} \left (-4 c e (3 b d-a e)+b^2 e^2+4 c e x (2 c d-b e)+16 c^2 d^2\right )}{4 e^4 (d+e x)}+\frac{3 \sqrt{c} \left (-4 c e (4 b d-a e)+3 b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{4 e^5}-\frac{3 (2 c d-b e) \left (-4 c e (4 b d-3 a e)+b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{-2 a e+x (2 c d-b e)+b d}{2 \sqrt{a+b x+c x^2} \sqrt{a e^2-b d e+c d^2}}\right )}{8 e^5 \sqrt{a e^2-b d e+c d^2}}+\frac{\left (a+b x+c x^2\right )^{3/2} (-b e+4 c d+2 c e x)}{2 e^2 (d+e x)^2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.368565, antiderivative size = 309, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.179, Rules used = {812, 843, 621, 206, 724} \[ -\frac{3 \sqrt{a+b x+c x^2} \left (-4 c e (3 b d-a e)+b^2 e^2+4 c e x (2 c d-b e)+16 c^2 d^2\right )}{4 e^4 (d+e x)}+\frac{3 \sqrt{c} \left (-4 c e (4 b d-a e)+3 b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{4 e^5}-\frac{3 (2 c d-b e) \left (-4 c e (4 b d-3 a e)+b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{-2 a e+x (2 c d-b e)+b d}{2 \sqrt{a+b x+c x^2} \sqrt{a e^2-b d e+c d^2}}\right )}{8 e^5 \sqrt{a e^2-b d e+c d^2}}+\frac{\left (a+b x+c x^2\right )^{3/2} (-b e+4 c d+2 c e x)}{2 e^2 (d+e x)^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 812
Rule 843
Rule 621
Rule 206
Rule 724
Rubi steps
\begin{align*} \int \frac{(b+2 c x) \left (a+b x+c x^2\right )^{3/2}}{(d+e x)^3} \, dx &=\frac{(4 c d-b e+2 c e x) \left (a+b x+c x^2\right )^{3/2}}{2 e^2 (d+e x)^2}-\frac{3 \int \frac{\left (2 \left (4 b c d-b^2 e-4 a c e\right )+8 c (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{(d+e x)^2} \, dx}{8 e^2}\\ &=-\frac{3 \left (16 c^2 d^2+b^2 e^2-4 c e (3 b d-a e)+4 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{4 e^4 (d+e x)}+\frac{(4 c d-b e+2 c e x) \left (a+b x+c x^2\right )^{3/2}}{2 e^2 (d+e x)^2}+\frac{3 \int \frac{2 \left (8 c (b d-a e) (2 c d-b e)-b e \left (4 b c d-b^2 e-4 a c e\right )\right )+4 c \left (16 c^2 d^2+3 b^2 e^2-4 c e (4 b d-a e)\right ) x}{(d+e x) \sqrt{a+b x+c x^2}} \, dx}{16 e^4}\\ &=-\frac{3 \left (16 c^2 d^2+b^2 e^2-4 c e (3 b d-a e)+4 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{4 e^4 (d+e x)}+\frac{(4 c d-b e+2 c e x) \left (a+b x+c x^2\right )^{3/2}}{2 e^2 (d+e x)^2}-\frac{\left (3 (2 c d-b e) \left (16 c^2 d^2+b^2 e^2-4 c e (4 b d-3 a e)\right )\right ) \int \frac{1}{(d+e x) \sqrt{a+b x+c x^2}} \, dx}{8 e^5}+\frac{\left (3 c \left (16 c^2 d^2+3 b^2 e^2-4 c e (4 b d-a e)\right )\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{4 e^5}\\ &=-\frac{3 \left (16 c^2 d^2+b^2 e^2-4 c e (3 b d-a e)+4 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{4 e^4 (d+e x)}+\frac{(4 c d-b e+2 c e x) \left (a+b x+c x^2\right )^{3/2}}{2 e^2 (d+e x)^2}+\frac{\left (3 (2 c d-b e) \left (16 c^2 d^2+b^2 e^2-4 c e (4 b d-3 a e)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c d^2-4 b d e+4 a e^2-x^2} \, dx,x,\frac{-b d+2 a e-(2 c d-b e) x}{\sqrt{a+b x+c x^2}}\right )}{4 e^5}+\frac{\left (3 c \left (16 c^2 d^2+3 b^2 e^2-4 c e (4 b d-a e)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{2 e^5}\\ &=-\frac{3 \left (16 c^2 d^2+b^2 e^2-4 c e (3 b d-a e)+4 c e (2 c d-b e) x\right ) \sqrt{a+b x+c x^2}}{4 e^4 (d+e x)}+\frac{(4 c d-b e+2 c e x) \left (a+b x+c x^2\right )^{3/2}}{2 e^2 (d+e x)^2}+\frac{3 \sqrt{c} \left (16 c^2 d^2+3 b^2 e^2-4 c e (4 b d-a e)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{4 e^5}-\frac{3 (2 c d-b e) \left (16 c^2 d^2+b^2 e^2-4 c e (4 b d-3 a e)\right ) \tanh ^{-1}\left (\frac{b d-2 a e+(2 c d-b e) x}{2 \sqrt{c d^2-b d e+a e^2} \sqrt{a+b x+c x^2}}\right )}{8 e^5 \sqrt{c d^2-b d e+a e^2}}\\ \end{align*}
Mathematica [A] time = 2.52841, size = 544, normalized size = 1.76 \[ \frac{-\frac{(a+x (b+c x))^{5/2} \left (4 c e (2 a e-3 b d)+b^2 e^2+12 c^2 d^2\right )}{2 (d+e x) \left (e (a e-b d)+c d^2\right )}-\frac{2 e^3 (a+x (b+c x))^{3/2} \left (2 c^2 e (2 a e (2 e x-3 d)+3 b d (5 d-2 e x))+b c e^2 (10 a e-15 b d+b e x)+b^3 e^3-4 c^3 d^2 (4 d-3 e x)\right )+6 e \sqrt{a+x (b+c x)} \left (e (a e-b d)+c d^2\right ) \left (4 c^2 e (a e (e x-3 d)+b d (7 d-2 e x))+b c e^2 (8 a e-13 b d+b e x)+b^3 e^3+8 c^3 d^2 (e x-2 d)\right )+6 \sqrt{c} \left (4 c e (a e-4 b d)+3 b^2 e^2+16 c^2 d^2\right ) \left (e (a e-b d)+c d^2\right )^2 \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )+3 (2 c d-b e) \left (e (a e-b d)+c d^2\right )^{3/2} \left (4 c e (3 a e-4 b d)+b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{2 a e-b d+b e x-2 c d x}{2 \sqrt{a+x (b+c x)} \sqrt{e (a e-b d)+c d^2}}\right )}{4 e^5 \left (e (b d-a e)-c d^2\right )}+\frac{(a+x (b+c x))^{5/2} (2 c d-b e)}{(d+e x)^2}}{2 \left (e (a e-b d)+c d^2\right )} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [B] time = 0.016, size = 10362, normalized size = 33.5 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]